Specific Heat Capacity Converter - Convert J/(kg·K), cal/(g·°C), BTU/(lb·°F) & More
Result:
1 J/(kg·K) = 0.00023901 cal/(g·°C)
How Specific Heat Capacity Conversion Works
Input Value
Enter heat capacity value
Select Units
Choose from and to units
Convert
Apply conversion formula
Conversion Formulas
J/(kg·K) to cal/(g·°C)
Formula: cal/(g·°C) = J/(kg·K) ÷ 4184
Example: 4184 J/(kg·K) = 4184 ÷ 4184 = 1 cal/(g·°C)
J/(kg·K) to BTU/(lb·°F)
Formula: BTU/(lb·°F) = J/(kg·K) ÷ 4186.8
Example: 4186.8 J/(kg·K) = 4186.8 ÷ 4186.8 = 1 BTU/(lb·°F)
kJ/(kg·K) to J/(kg·K)
Formula: J/(kg·K) = kJ/(kg·K) × 1000
Example: 1 kJ/(kg·K) = 1 × 1000 = 1000 J/(kg·K)
Wh/(kg·K) to J/(kg·K)
Formula: J/(kg·K) = Wh/(kg·K) × 3600
Example: 1 Wh/(kg·K) = 1 × 3600 = 3600 J/(kg·K)
Specific Heat Capacity Conversion Table
| J/(kg·K) | cal/(g·°C) | BTU/(lb·°F) | kJ/(kg·K) | kcal/(kg·°C) | Wh/(kg·K) |
|---|---|---|---|---|---|
| 100 | 0.0239 | 0.0239 | 0.100 | 0.0239 | 0.028 |
| 500 | 0.1195 | 0.1194 | 0.500 | 0.1195 | 0.139 |
| 1000 | 0.2390 | 0.2388 | 1.000 | 0.2390 | 0.278 |
| 1500 | 0.3585 | 0.3583 | 1.500 | 0.3585 | 0.417 |
| 2000 | 0.4780 | 0.4777 | 2.000 | 0.4780 | 0.556 |
| 2500 | 0.5975 | 0.5971 | 2.500 | 0.5975 | 0.694 |
| 3000 | 0.7170 | 0.7165 | 3.000 | 0.7170 | 0.833 |
| 4000 | 0.9560 | 0.9554 | 4.000 | 0.9560 | 1.111 |
| 4184 | 1.0000 | 0.9993 | 4.184 | 1.0000 | 1.162 |
| 5000 | 1.1950 | 1.1942 | 5.000 | 1.1950 | 1.389 |
| 6000 | 1.4340 | 1.4331 | 6.000 | 1.4340 | 1.667 |
| 8000 | 1.9120 | 1.9108 | 8.000 | 1.9120 | 2.222 |
| 10000 | 2.3901 | 2.3885 | 10.000 | 2.3901 | 2.778 |
| 15000 | 3.5851 | 3.5827 | 15.000 | 3.5851 | 4.167 |
| 20000 | 4.7801 | 4.7769 | 20.000 | 4.7801 | 5.556 |
Specific Heat Capacity Units Progression Chart
100 J/(kg·K)
500 J/(kg·K)
1000 J/(kg·K)
2000 J/(kg·K)
4000 J/(kg·K)
5000 J/(kg·K)
Practice Problems
Problem 1:
Convert 4184 J/(kg·K) to cal/(g·°C)
Solution: 4184 ÷ 4184 = 1 cal/(g·°C)
Problem 2:
Convert 0.5 cal/(g·°C) to J/(kg·K)
Solution: 0.5 × 4184 = 2092 J/(kg·K)
Problem 3:
Convert 2 kJ/(kg·K) to J/(kg·K)
Solution: 2 × 1000 = 2000 J/(kg·K)
Problem 4:
Convert 1 BTU/(lb·°F) to J/(kg·K)
Solution: 1 × 4186.8 = 4186.8 J/(kg·K)
Problem 5:
Convert 1.5 Wh/(kg·K) to J/(kg·K)
Solution: 1.5 × 3600 = 5400 J/(kg·K)
Daily Uses of Specific Heat Capacity
Cooking pot materials affect heating time and energy efficiency
Car radiator coolant selection based on heat capacity properties
Building insulation materials chosen for thermal storage capacity
Water heating systems designed using water heat capacity values
Electronic device cooling systems utilize material heat capacities